An object of height 5cm is kept at a distance of 10 cm in front of a concave mirror. The focal length Of the mirror is 5cm. Find the distance to image and size of the image.
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u=-5 cm, f=10 cm
We know that
v
1
+
u
1
=
f
1
⇒
v
1
+
(−5)
1
=
10
1
⇒
v
1
=
20
1
+
5
1
=
10
3
∴v=
3
10
cm=3.33cm
The position of the image is 3.33 cm behind the convex mirror.
Magnification, m=−
u
v
=−
−5
3.33
=0.66
The image is virtual and erect.
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