An object of height 5cm is placed at a distance of 15 cm in front of a concave lens power-10 d. find the size of the image
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Answer:
Concave lens
ho=+4 cm
u=-15 cm
P=1/f f=Focal Length
-10 =1/f
f=(1/-10)×100 cm
f=-10cm
using lens formula
1/f=1/v-1/u
⇒1/v=1/f+1/u
⇒1/v= -1/10 -1/15
⇒1/v=(-3-2)/30
⇒1/v=-5/30
⇒1/v=-1/6
Image distance (v)= -6 cm
hi/ho=v/u
⇒hi=v/u×ho
⇒hi=-6/-15 ×5
⇒hi=2/5 ×5
⇒hi=10/5cm
⇒hi=2 cm
Image Height =2 cm Answer.
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