an object of height 5cm is placed perpendicular to the principal axis of concave lens of length 10 cm if the distance of the object from the optical centre of lens is 20 cm determine the position ,nature and size of image formed using the lens formula.
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Hello...
Friend.....
.
Follow the step by step.
h=5 f=+10 u=-20
.by using lens formula
1/f=1/u+1/v
1/v=1/u + 1/f
= 1/-20+ 1/10
=-1+2/20
1/v = 1/20
v= 20
.
image is real and inverted
Friend.....
.
Follow the step by step.
h=5 f=+10 u=-20
.by using lens formula
1/f=1/u+1/v
1/v=1/u + 1/f
= 1/-20+ 1/10
=-1+2/20
1/v = 1/20
v= 20
.
image is real and inverted
SivaBika:
Isn’t focal length of a concave lens negative? Also how is the value of length of the lens taken as focal length? Is it not equal to the radius of curvature of the lens?
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