Question

An object of height 6 cm is placed at a distance of 10 cm from a convex mirror with radius of curvature 30 cm.Find the position, nature and the height of its image.

Answer 1

Explanation:

See answer in above attachment

Answer 2

Answer:

Image formed is real and erect with height of 10 cm and at a distance 6 cm

Explanation:

• As it is known to us that for convex mirror $\frac{1}{u} +\frac{1}{v} =\frac{1}{f}$ where u = distance of the object and v = distance of image from center of curvature and f is the distance of focus.
• Here in the question it is given to us that u = -10 cm and f = 15 cm
• So the distance of image is
  $\frac{1}{v} + \frac{1}{-10}=\frac{1}{15}\\ \frac{1}{v} = \frac{5}{30}\\v = 6$
• Hence the image is formed at 6 cm.
• The height of the image is given by
  $\frac{h_1}{h_2} =\frac{v}{-u} \\h_1 = 10$
• Image formed is real and erect with height of 10 cm and at a distance 6 cm
  #SPJ3