An object of height 7 cm is kept at a distance of 25 cm in front of a concave mirror. The focal length of the mirror is 15 cm. At what distance from the mirror should a screen be kept so as to get a clear image? What will be the size and nature of the image? (Answer: 37.5 cm and 10.5 cm. Image is real). Solve the example.
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whereobject distance (u)=−25cm
image distance (v)=?focal length(f)=−15cm(for concave mirror)Inserting these values we get1v−125=−115⇒1v=125−115=3−575=−275
v=−37.5
So real image (as represented by -ve image dist.) will be formed at distance 37.5cm
image distance (v)=?focal length(f)=−15cm(for concave mirror)Inserting these values we get1v−125=−115⇒1v=125−115=3−575=−275
v=−37.5
So real image (as represented by -ve image dist.) will be formed at distance 37.5cm
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