An object of height 7 cm is kept at distance 25 cm front of concave
mirror . The focal Length of the mirror is 15 cm, where should a
screen be placed to get a dear image.
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Physics
An object of size (height) 7cm is placed at 25cm in front of concave mirror of focal length 15cm. At what distance from the mirror should a screen be placed, so that we can get a sharp and clear image? Find nature and size (height) of the image.
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Size of object h
o
=7cm
Size of the object h
o
=?
Focal length f=−15cm
Object distance u=−25cm
Image distance v=?
Using mirror formula,
f
1
=
v
1
+
u
1
−15
1
=
v
1
+
−25
1
v
1
=
75
−5+3
v=−37.5cm
Hence, position of image at 37.5cm infront of the mirror.
Magnification(M)=
h
o
h
i
=
u
−v
=
−25
37.5
=−1.5
h
i
=−1.5×h
O
h
i
=−1.5×7=−10.5cm
Hence,size of image is −10.5cm.
Nature of image is real,inverted and magnified.
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