an object of height 9cm is placed at a distance of 14cm infront of a convex lens of focal length 12cm. find the position,nature and size of the object
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Explanation:
f = 12cm
h = 9cm
u = - 14cm
we know that,
1/v - 1/u = 1/f
1/v - 1/ -14 = 1/12
1/v = 1/12 - 1/14
TAKING L.C.M OF 14 AND 12, WE GET : 168 AS THE DENOMINATOR.
Therefore, 1/v = 14-12/ 168 = 2/168
Therefore,
v = 84cm.
For size of the image,
v/u = h`/h => 84/-14 = h`/9
=> 84X9/-14 = -54cm
Image size = -54cm
Thus, The image size is smaller than the object size, and the image formed is real and inverted.
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