An object of height is 5cm is kept as a distance of 25cm from a concave mirror of focus 10cm find the position size and nature of image
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.firstly we have to find v image distance.
we use formula for this 1/v+1/u=1/f.
now we know u=25
f=10
therefore we get .
v=16.67
there fore position of image will be -16.67cm and nature of image will be real and inverted .
now for size.
we use formula
h2/h1=-v/u
h2/5=16.67/25
h2= 83.35/25
therefore size of image will be 3.34cm(approx).
we use formula for this 1/v+1/u=1/f.
now we know u=25
f=10
therefore we get .
v=16.67
there fore position of image will be -16.67cm and nature of image will be real and inverted .
now for size.
we use formula
h2/h1=-v/u
h2/5=16.67/25
h2= 83.35/25
therefore size of image will be 3.34cm(approx).
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