an object of hight 7 cm kept at a distance of 25cm in front of a concave mirror th focal length of the mirror is 15 cm at what distance from the mirror should a screen be kept so as to get a clear image what will be the size and nature of image
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for concave lens ......everything is in negative...so v = -5 cm
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u=-25cm,height of object = H =7 Cm,f=-15 cm,v=?
1/v-1/u=1/f(mirror formula)
1/v=1/-15+1/-25
=-1/15-1/25
= -5-3/75
=-8/75=-0.10.
magnification,M=-v/u.
=-(-8/75)÷25/1
=-8/3
THEREFORE THE NATURE OF IMAGE IS REAL AND INVERTED.
SIZE IS -8/3 TIMES THE ORIGINAL SIZE,THAT IS ,IT IS DIMINISHED..
Hope that helps...
please mark it as brainliest..
1/v-1/u=1/f(mirror formula)
1/v=1/-15+1/-25
=-1/15-1/25
= -5-3/75
=-8/75=-0.10.
magnification,M=-v/u.
=-(-8/75)÷25/1
=-8/3
THEREFORE THE NATURE OF IMAGE IS REAL AND INVERTED.
SIZE IS -8/3 TIMES THE ORIGINAL SIZE,THAT IS ,IT IS DIMINISHED..
Hope that helps...
please mark it as brainliest..
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