an object of length 2.5 CM at a distance of 1.5 f from a concave mirror when f is the magnitude of the focal length of the mirror find the length of the image and nature of the image
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Focal length F=−f
and u=−1.5f
1u+1v=1F
1−1.5f+1v=−1f
1v=11.5f−1f
=−−13f
v=−3f
Now m=−vu=−3f1.5f=−2
or h2h=−2
or h2=−2h1=−5cm
the image is 5 cm long.
The minus sign shows that it is inverted.
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