an object of mass 0.4 kg is whirled in a horizontal circle of radius 2 m. if is undergoes 60 revolutions min calculate the centripital force acting on it
Answers
Answered by
25
we know that
v= rw
w = angular speed
for 1 revolution , w = 2π/60 rad/s = 0.105 rad/s
hence for 60 revolution
w = 60×0.105 rad/s
w = 6.28 rad/s
therefore, v = rw = 2×6.28 = 12.57 m/s
hence
centripetal force = f
f= m•v^2/r ={ 0.4× (12.57)^2 } / 2
f= 31.55 N
v= rw
w = angular speed
for 1 revolution , w = 2π/60 rad/s = 0.105 rad/s
hence for 60 revolution
w = 60×0.105 rad/s
w = 6.28 rad/s
therefore, v = rw = 2×6.28 = 12.57 m/s
hence
centripetal force = f
f= m•v^2/r ={ 0.4× (12.57)^2 } / 2
f= 31.55 N
Similar questions