Question

An object of mass 0.5 kg is whirled at the
end of a string 0.8 m long. If the string makes
three revolutions in 1.2 s, find the tension in
the string.​

Answer 1

Answer:

The tension in  the string is 98.7 N

Explanation:

An object of mass 0.5 kg is whirled at the  end of a string 0.8 m long.

according to the problem the string makes  3 revolutions in 1.2 sec.

Hence, T= 1.2/3

               = 0.4 s

The velocity of the object:

take v is the velocity,

v= 2πr/t = 4π,

Now the tension in the string is:

T=mv^2/r

0.5 x 16π^2/0.8

 =98.7 N

Answer 2

Answer:

35.6

Explanation:

answer

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