An object of mass 1.5 kg is moving with a velocity of 20 m/s. A force increases its velocity by 5 m/s. Find the work done by the force?
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Answer:
-210J
Explanation:
(K. E)v = 1/2 mv2
Where,
K. E = Kinetic energy of the object
v = velocity of the object
Kinetic energy when the object was moving with a velocity of 5 m/s
(K. E)5 = 1/2 × 20 × (5)2
(K. E)5 = 250 J
Kinetic energy when the object was moving with a velocity 2 m/s
(K. E)2 = 1 /2 × 20 × (2)2
(K. E)2 = 40 J
Work done = Change in kinetic energy
= 40 J – 250 J
= – 210 J
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