Question

. An object of mass 10 kg is acted upon by a constant

retarding force of 500 N. If it were initially

moving with a speed of 500 ms–1, in how much

time will it come to rest?
PLEASE answer only if you know
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Answer 1

Answer:

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Answer 2

Given, F = - 500 N (-ve for retardation)

m = 10kg

u = 500 m/s

v = 0

Since, F = ma

Therefore, a = F/m

a = -500/10

a = -50 m/s²

Now, using v = u + at

Therefore, t = v - u/a

t = 0 - 500/ -50

t = -500/-50

t = 10s

So,

Time at which it will come to rest is 10 seconds.