Question

An object of mass 100 kg is accelerated uniformly from a velocity of 5 ms-1 to 8 ms-1 in 6 s. Calculate the initial and final momentum of the object. Also, find the magnitude of the force exerted on the object.

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Answer 1

hey mate!!
_______________________________


Given,

mass = 100Kg
vi = 5m/s
vf=8m/s

P = momentum = MV

P1 = 100*5 = 500Kg m/s
p2 = 100*8 = 800kg m/s

Force = Rate of change of momentum

F = 800-500/ 6 = 50N

hope it helps! !

#Jaihind

Answer 2

$\Huge\orange{\boxed{\boxed{\underline{ANSWER}}}}$

MOMENTUM : Is defined as product of mass and velocity and having the same direction as that of the velocity.

It is represented by the letter p . Given by p = m × v, where m is mass and v is a velocity.

The S.I unit is Kgm/s.

• m =  100 kg

        u  =  5 m/s

        v  = 8 m/s

         t  = 6s

          p₁   =  ?

          p₂  =  ?

            F  =   ?

Initial momentum p₁  = mu

                                  = 100 × 5

                                  = 500 kg m/s

Final Momentum p₂  = mv

                                  = 100 × 8

                                  =  800 kg m/s

Force exerted on the object F = ma

                                                   = 100 ( v - u / t )

                                                   =   100 ( 8 - 5 / 6 )

                                                   =  100 × 3/6

                                   F       =  50 N