Question

An object of mass 100kg is accelerated uniformly from a velocity of 5m/s to 8m/s in 6s.nCalculate the initial and final momentum of the object.Also,find the magnitude of the force exerted on the object.

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Answer 1

$\huge\star\underline\mathfrak\red{Answer:-}$

Given:

u = 5m/s

v= 8m/s

m= 100kg

t= 6s

mu = 100×5 = 500 kg m/s

MV= 100×8 = 800 kg m/s

F = $\frac{mv - mu}{t}$

= $\frac{m(v - u)}{t}$

= $\frac{800 - 500}{6}$

= $\frac{300}{6}$

= 50N

Answer 2

mass = m = 100kg

initial velocity = u = 5m/s

final velocity = v = 8m/s

Initial momentum = mu = 100×5 = 500kg m/s

Final momentum = mv = 100×8 = 800kg m/s

Force = Rate of change of momentum

= ∆p/∆t = Change in momentum/Change in time

= (800-500)/6

= 300/6 = 50N

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