An object of mass 10kg 8s dropped from a height of 100mfind its kinetic energy
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hiiii mate hope helped u
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mitajoshi11051976:
when g is not given we must take g=9.8m/s^2. edit your answer
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m=10kg
t=8s
h=100m
g=9.8m/s^2
u=0m/s
v=?
K.E.=?
v=u+gt
=0+(9.8)×(8)
=98÷10×8
=78.4m/s
K.E.=1/2.m.v^2
=1÷2×10×(78.4)^2
=5×78.4×78.4
= 30732.8J
i hope it helps you
t=8s
h=100m
g=9.8m/s^2
u=0m/s
v=?
K.E.=?
v=u+gt
=0+(9.8)×(8)
=98÷10×8
=78.4m/s
K.E.=1/2.m.v^2
=1÷2×10×(78.4)^2
=5×78.4×78.4
= 30732.8J
i hope it helps you
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