Question

An object of mass 10kg fall from point A 100m high to the point B 35m from ground point find change in its potential energy while moving from point A to B what will e it's kinetic energy at point A just before touching ground​

Answer 1

Answer:

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Answer 2

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It is given that height of point A from ground is 100m and height of point B from ground is 35m.

Now important Keywords--------------->

Mass of object = 10kg

Acceleration = g = 9.8m/s^2

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Now change in potential energy of object =

potential energy at point A - potential energy at point B

Since, Potential energy of an object =

$m \times g \times h$

Where (m) is mass (g) is acceleration due to gravity and (h) is the height of object from ground.

Thus potential energy of object at point A is

$10 \times 9.8 \times 100$

$= 9800joules$

Now potential energy of object at point B is

$10 \times 9.8 \times 35$

$= 3430joules$

Now change in potential energy of ball is

9800joules - 3430joules.

$= 6370joules$

Now according to law of conservation of energy it's potential energy will be equal to it's kinetic energy a particular point.

Thus kinetic energy of object at point A will be

9800joules.

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BY SCIVIBHANSHU

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