the difference in the value of g at pole Satay latitude is 3 by 4 w r square then the latitude angle is
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1
Answer:
The effective value of g at any latitude angle θ is :
⇒g
eff
=g−ω
2
Rcos
2
θ (where ω= angular velocity of earth and R= radius)
⇒g−ω
2
Rcos
2
θ=
4
3
Rω
2
⇒cos
2
θ=
Rω
2
g
−
4
3
On substituting g=9.8m/s
2
,R=6400km and ω=
T
2π
Where T=204 hours
cos
2
θ=
4
1
⇒cosθ=
2
1
So, θ=60
∘
is the latitude
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