An object of mass 16kg is moving with an acceleration of 3/ms². Calculate the applied force. If the same force is applied on an object of mass 24 kg,how much will be the acceleration.?
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Answer:
P=Rs.1200,A=Rs.1632,t=4
A=P+
100
P×r×t
⟹1632=1200
100
1200×r×4
⟹r=9%
Now if rate is increased by 1% then r=(9+1)%=10%then amount will be,
A=P+
100
P×r×t
⟹A=1200
100
1200×10×4
⟹A=Rs.1680
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