Question

An object of mass 1kg acquires a speed of 10 m/s when pushed forward. What is the impulse given to the object?

Answer 1

Given:

Initial velocity of object,u= 0 m/s

Final velocity of object,v= 10 m/s

Mass of object,m= 1 kg

To Find:

The impulse given to the object

Solution:

We know that,

• The expression of impulse(J) is given by

$\pink{\boxed{\bf{J=m.\triangle v}}}$

where,

m is mass

Δv is change in velocity

$\rule{190}{1}$

Let the change in velocity of object be Δv

So,

$\longrightarrow\rm{\triangle v=v-u}$

$\longrightarrow\rm{\triangle v=10-0}$

$\longrightarrow\rm{\triangle v=10\ m/s}$

$\rule{190}{1}$

Let the impulse given to the object be J

So,

$\longrightarrow\rm{J=m.\triangle v}$

$\longrightarrow\rm{J=1\times 10}$

$\longrightarrow\rm\green{J=10\ Ns}$

Hence, the impulse given to the object is 10 Ns.

Answer 2

Answer:

10kgm/s

Explanation:

Impusle is a sudden huge force applied for a short period of time

Impulse J= F.dt = m∆v

F is force, dt is small change in time, m is mass and ∆v is change in velocity

J=m∆v

∆v=final v -initial v

Final v is 10 m/s and initial v is 0 m/s

∆v =(10-0)m/s

J= 1*10 kgm/s

= 10 kgm/s