Question

An object of mass 1kg is rest . A constant force of 10 Newton is applied on it for 2 seconds . Find the work by the force on the object .​

Answer 1

Answer:

20 Joules

Explanation:

Work done= W.D= Force x Displacement

Therefore, W.D= 10Nx Displacement

Now, find the displacement by using the formula v=u+at

U= initial velocity=0, since body is at rest and F=ma

a=F/m Therefore, a=10N/1kg = 1m/second-square

Now, using v=u+at, v=0 + 1.t Therefore, v=0 + (1x2)=2m/s

Therefore, W.D=FxD = 10N x 2m/s = 20 Joules

Answer 2

Answer:

200 jule approximately.....

Explanation:

F=10,m=1 kg now using second low of motion F=m.a,so we get value of a* now using second equation of motion so we get s* now using formula of work done W= F.s......