an object of mass 20 kg and velocity of 20cm/s from rest in 5 sec find the force applied on it in newton and dyne
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Answered by
1
20cm/s=0.2m/s
f=change in momentum /time=
0.2-0/5=0.2/5=0.04N
one newton =10 power 5 dyne
so 0.04N=4000dyne(0.04*100000)
f=change in momentum /time=
0.2-0/5=0.2/5=0.04N
one newton =10 power 5 dyne
so 0.04N=4000dyne(0.04*100000)
Answered by
1
Given
Mass _ 20 kg
Velocity_0.2 m/s
Time_5 s
Using newtons equation of motion
v= u+ at
0.2 = 0+ a×5
a= 0.04 m/s2
From second law of motion
F= ma = 20 × 0.04
= 0.8 N
Force in dyne = 80000 Dyne
Because 1 N= 100000 Dyne
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Mass _ 20 kg
Velocity_0.2 m/s
Time_5 s
Using newtons equation of motion
v= u+ at
0.2 = 0+ a×5
a= 0.04 m/s2
From second law of motion
F= ma = 20 × 0.04
= 0.8 N
Force in dyne = 80000 Dyne
Because 1 N= 100000 Dyne
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