Question

An object of mass 200kg is accelerated uniformly from a velocity of 12m/s to 15m/s in 3s .Find the magnitude of force exerted on the object. *
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Answer 1

Answer:

Initial velocity of the object (u) = 5 m/s

Final velocity of the object (v) = 8 m/s

Mass of the object (m) = 100 kg

Time take by the object to accelerate (t) = 6 s

Initial momentum = mu = 100 × 5

⇒ mu = 500 kg m/s

Final momentum = mv = 100 × 8

⇒ mv = 800 kg m/s

Let us calculate the Force exerted on the object (F)

F = (mv – mu) / t

F = (800 – 500)/6

F = 300 / 6

F = 50 N

Initial momentum of the object is 500 kg m sˆ1.

Final momentum of the object is 800 kg m sˆ1.

Force exerted on the object is 50 N.

Answer 2

$\sf\green{Answer}$

Force = ma

Force = m(v - u)/t

Force = 200(20 - 10)/2

Force = (4000 - 2000)/2

Force = 2000/2

Force = 1000 N

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