Question

an object of mass 200kg is accelerated uniformly from a velocity of 10m/s to 20m/s in 2s. calculate the

(a) initial momentum of the object.

(b) final momentum of the object.

(c) magnitude of force exerted on the object.

Answer 1

MASS = 200 KG

INITIAL VELOCITY = 10 M/S

FINAL VELOCITY = 20 M/S

A) INITIAL MOMENTUM = MASS × INITIAL VELOCITY

= 200 × 10

= 2000 KGM/S

B) FINAL MOMENTUM = MASS × FINAL VELOCITY

= 200 × 20

= 4000 KGM/S

C) FORCE = CHANGE IN MOMENTUM / TIME TAKEN

= (4000-2000)/2

= 2000/2

= 1000 NEWTONS

PLZ MARK IT AS BRAINLIEST ANSWER AND DROP A ♥

Answer 2

mass (m)= 200kg

initial velocity (u)= 10m/s

final velocity (v)= 20m/s

time taken (t)= 2s

first, initial momentum of the body

p=mu

=200 kg  x 10m/s= 2000 kg m/s

now, final momentum of the body

p=mv

=200kg x 20m/s =4000 kg m/s

finally, the magnitude of force

F=ma

F=m(v-u) / t

= 200(20-10) / 2



=1000N 

so the initial momentum is 2000 kg m/s

the final momentum is 4000kg m/s

and the magnitude of the force is 1000N