answer the 6th Q plz
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Hope u like my process
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a)
![( {16}^{( - \frac{1}{5}) } ) \\ = {( \frac{1}{16} )}^{ \frac{1}{5} } \\ = \sqrt[5]{ \frac{1}{ {2}^{4} } } \\ = \sqrt[5]{ \frac{2}{ {2}^{5} } } \\ = \frac{ \sqrt[5]{2} }{2} ....answer..](https://tex.z-dn.net/?f=%28+%7B16%7D%5E%7B%28+-++%5Cfrac%7B1%7D%7B5%7D%29+%7D+%29+%5C%5C++%3D++%7B%28+%5Cfrac%7B1%7D%7B16%7D+%29%7D%5E%7B+%5Cfrac%7B1%7D%7B5%7D+%7D++%5C%5C++%3D++%5Csqrt%5B5%5D%7B+%5Cfrac%7B1%7D%7B+%7B2%7D%5E%7B4%7D+%7D+%7D++%5C%5C++%3D+++%5Csqrt%5B5%5D%7B+%5Cfrac%7B2%7D%7B+%7B2%7D%5E%7B5%7D+%7D+%7D++%5C%5C++%3D++%5Cfrac%7B+%5Csqrt%5B5%5D%7B2%7D+%7D%7B2%7D+....answer.. "( {16}^{( - \frac{1}{5}) } ) \\ = {( \frac{1}{16} )}^{ \frac{1}{5} } \\ = \sqrt[5]{ \frac{1}{ {2}^{4} } } \\ = \sqrt[5]{ \frac{2}{ {2}^{5} } } \\ = \frac{ \sqrt[5]{2} }{2} ....answer..")
b)
![( {(343)}^{ \frac{1}{3} } )^{ - 2} \\ = {( \sqrt[3]{343} )}^{ - 2} \\ = {( \frac{1}{ \sqrt[3]{ {7}^{3} } } )}^{2} \\ = {( \frac{1}{7}) }^{2} \\ = \frac{1}{49}](https://tex.z-dn.net/?f=%28+%7B%28343%29%7D%5E%7B+%5Cfrac%7B1%7D%7B3%7D+%7D+%29%5E%7B+-+2%7D++%5C%5C++%3D++%7B%28+%5Csqrt%5B3%5D%7B343%7D+%29%7D%5E%7B+-+2%7D++%5C%5C++%3D++%7B%28+%5Cfrac%7B1%7D%7B+%5Csqrt%5B3%5D%7B+%7B7%7D%5E%7B3%7D+%7D+%7D+%29%7D%5E%7B2%7D++%5C%5C++%3D++%7B%28+%5Cfrac%7B1%7D%7B7%7D%29+%7D%5E%7B2%7D++%5C%5C++%3D++%5Cfrac%7B1%7D%7B49%7D+ "( {(343)}^{ \frac{1}{3} } )^{ - 2} \\ = {( \sqrt[3]{343} )}^{ - 2} \\ = {( \frac{1}{ \sqrt[3]{ {7}^{3} } } )}^{2} \\ = {( \frac{1}{7}) }^{2} \\ = \frac{1}{49}")
Hope this is ur required answer
Proud to help you
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a)
b)
Hope this is ur required answer
Proud to help you
thnx for the brainliest one
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beta sada kush raho
thanks aunty
thanks for what
u said noo
kya
aunty ji paaye laagu
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