An object of mass 40 kg is raised to a height of 5 m above the ground. What is its
potential energy? If the object is allowed to fall, find its kinetic energy when it is half
way down.
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by conservation of mechanical energy we get
M×g×5=M×g×5÷2 +(Mv^2)÷2. (v=gt)
implies (M=40)×g×2•5=M÷2×g^2×t^2
implies as t=2 by t^2 =2g÷5
as t=2 we get 20×10×10×4=8000
M×g×5=M×g×5÷2 +(Mv^2)÷2. (v=gt)
implies (M=40)×g×2•5=M÷2×g^2×t^2
implies as t=2 by t^2 =2g÷5
as t=2 we get 20×10×10×4=8000
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