An object of mass 40 kg is raised to a height of 5 m above the ground. What is
its potential energy? If the object is allowed to fall, find its kinetic energy when
it is half-way down
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Solution :-
- Mass of the object = 40 kg
- Height of the object from the ground = 5 m
- Acceleration due to gravity (g) = 10 m /s²
As no external force is acting on the system the total energy of the system is conserved
By applying law of conservation of energy ,
➠ KEi + PEi = KEf + PEf
here ,
- KEi = 0 ( initially the object is at rest )
- PEi = mgh = 40 x 10 x 5 = 2000 J
- PEf = mgh' = mgh /2 = 40 x 10 x 5 / 2 = 400 x 2.5 = 1000 J
Now let's substitute the obtained values in the above equation ,
➠ 0 + 2000 = KEf + 1000
➠ KEf = 2000 - 1000
➠KEf = 1000 J
The final kinetic energy of the body is 1000 J
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