Question

An object of mass 40 kg. is raised toa height of 5 m. from the ground . g=10 m/2. Calculate the work done​

Answer 1

Answer:

Given:

Mass (m) = 40 kg

Acceleration due to gravity (g)= 10m/s²

Height (h)= 5m

Potential energy= m × g× h

P.E= 40 × 10 × 5 = 2000J

Potential energy = 2000J ( 2000 joules)

At a height of 5 metre object has a potential energy of 2000 J.

When this object is allowed to fall and it is Half way down its height above the ground will be half of 5 m= 5/2= 2.5m.

P.E at Half way down= m× g×h

P.E= 40× 10 × 2.5= 1000J

[h= 2.5 m]

Potential Energy at Half way down= 1000 joules.

According to law of conservation of energy:

Total potential energy= potential energy at Half way down+ kinetic energy at Half way of a down

2000 = 1000 + K.E at Half way down

K.E at Half way down= 2000- 1000= 1000J

Kinetic energy at half way down= 1000 joules.

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Answer 2

Answer:

2000 Joules

Explanation:

Work Done = Force * Displacement

Force = Mg = 40*10 = 400N

Displacement = 5 metre

Applying formula,

Work Done = 400*5 = 2000 Nm = 2000 Joules  

Thank you.