Physics, asked by Anonymous, 4 days ago

An object of mass 400 grams is whirled in a horizontal circle of radius 2 m. If it performs 60 rpm, calculate the centripetal force acting on it.​

Answers

Answered by nilesh102
1

Given data :

• Mass of an object, m = 400 gram

• Radius of the horizontal circle, r = 2 m

• Frequency of an object, f = 60 rpm

Solution : Here, first we have to convert unit of mass and frequency of an object into kg and rev/sec or Hz respectively.

➜ m = 400 grams = (400/1000) kg = 0.4 kg

➜ f = 60 rpm = (60/60) rev/sec = 1 Hz

Here, we know that

➜ Angular velocity, ω = 2πf ----{1}

Now,

➜ Centripetal force, F = mω²r

[From {1}]

➜ Centripetal force, F = m * (2πf)² * r

➜ Centripetal force, F = m * 4 * π² * f² * r

➜ Centripetal force, F = 0.4 * 4 * (22/7)² * (1)² * 2

➜ Centripetal force, F = 1.6 * (484/49) * 1 * 2

➜ Centripetal force, F = 1.6 * (484/49) * 2

➜ Centripetal force, F = 3.2 * (484/49)

➜ Centripetal force, F = (3.2 * 484)/49

➜ Centripetal force, F = 1548.8/49

➜ Centripetal force, F = 31.6081 N

Answer : The centripetal force acting on the object is 31.6081 N.

More info :

Angular velocity : The time rate of angular displacement of a particle performing circular motion is called the angular velocity.

Centripetal force : centripetal force is the force required to provide centripetal acceleration to a particle to move it in a circular path.

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