Question

An object of mass 40kg is raised to a height of 5 m above the ground . What is its potential energy b?if the object is allowed to fall , find its kinetic energy when it is half -way down

Answer 1

Potential energy=mgh

=40×9.8×5

=1960

We know, 2as=v^2-u^2

2×9.8×2.5=v^2-0^2

49=v^2

V=7

Kinetic energy=1/2mv^2

=1/2×40×49

=980

Answer 2

_/\_Hello mate__here is your answer--

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Given:-

m = 40 kg

g = 9.8 m/s^2

h = 5 m

We know that,

potential energy = mgh

= 40 × 9.8 × 5 J

= 1960 J

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♦♦The total mechanical energy (Kinetic and potential energy) of an object remains constant. (law of conservation of energy)

Therefore, when the object is half-way down, its potential energy become half the original energy and remaining half converted into kinetic energy.

Hence, the kinetic energy = ½ (1960) J = 980 J

I hope, this will help you.☺

Thank you______❤

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