an object of mass 5 kg covers a distance of 100m from it's position of rest in 5s . what is the force acting on it ( please give explanation too)
Answers
Answer:
hope it help u and u may like the explanation
Required Answer :
The force acting on the body = 40 N
Given :
Mass of an object (m) = 5 kg
Distance travelled by the object (s) = 100 m
Initial velocity of the object (u) = 0 m/s
Time (t) = 5 seconds
To find :
Force acting on the object
Solution :
To calculate the force acting on the object, we will use the following formula :
- F = ma
where,
- F denotes the force
- m denotes the mass of the object
- a denotes the acceleration
We don't have the value of acceleration. So, firstly we will calculate the acceleration by using the second equation of motion.
Second equation of motion :
- s = ut + ½ at²
where,
- s denotes the distance/displacement
- u denotes the initial velocity
- a denotes the acceleration
- t denotes the time taken
Substituting the given values :
= 100 = (0)(5) + ½ × a × (5)²
= 100 = 0 + ½ × a × 25
= 100 = 25/2 × a
= 100 × 2/25 = a
= 4 × 2 = a
= 8 = a
Acceleration of the object = 8 m/s²
Now, we can calculate the force acting on the body by directly applying the values in the formula of force.
= Force = ma
= Force = 5 × 8
= Force = 40
Therefore, the force acting on the body = 40 N