Question

An object of mass 5 kg is moving with a velocity of 10 metre per second. a force is applied so that in 20 s, it attains a velocity of 25 meter per second. what is the force applied on the object

Answer 1

Explanation:

Apply equation of kinematic

v=u+at

Acceleration, a=

t

v−u

=

20

25−10

=0.75ms

−2

Force= mass x acceleration

F=5×0.75=3.75N

Hence, force is 3.75N

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Answer 2

Given ;-

• Initial velocity = u = 10 m/s.

• Final velocity = v = 25 m/s.

• Mass of the object = m = 5 kg.

• Time taken = t = 20 sec.

To Find :-

• Force applied on the object = f = ?

Solution :-

We know that,

• Force = Mass × Acceleration.

Here,

• Force = ?

• Mass = 5 kg.

• Acceleration = ?

To Find Acceleration :-

➠  v = u + at

➠  25 = 10 + (a × 20)

➠  25 = 10 + 20a

➠  20a = 25 - 10

➠  20a = 15

➠  a = 15/20

➠  a = 0.75 m/s².

Now,

Calculate the force :-

➩  5 × 0.75

➩  3.75 N.

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Equations of motion:

• v = u + at

• s = ut + ½at²

• v² – u² = 2as

Here,

✪  v = final velocity = m/s

✪  u = initial velocity = m/s

✪  a = acceleration = m/s^2

✪  s = distance/displacement = m

✪  t = time = sec

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