Question

An object of mass 50 gm is moving with a velocity of 80 m/s is brought to rest in 8 sec. Calculate the force of friction​

Answer 1

Answer:

Now,

v

2

=u

2

+2as

0=(500)

2

+2(a)

100

(10)

⇒a=−1250000m/s

Average retarding force =

1000

50

×(1250000)

⇒F

av

=62500N

K.E=

2

1

mv

2

=

2

1

×

1000

50

×(500)

2

K.E=

4

25000

=6250joule

Answer 2

Answer:

6250

Explanation:

Answer

Now,

v

2

=u

2

+2as

0=(500)

2

+2(a)

100

(10)

⇒a=−1250000m/s

Average retarding force =

1000

50

×(1250000)

⇒F

av

=62500N

K.E=

2

1

mv

2

=

2

1

×

1000

50

×(500)

2

K.E=

4

25000

=6250joule

solution