Question

An object of mass 500 g is dropped from a tower of height 5. Calculate its momentum when it touches the ground.

(g = 10 m/s²)

Answer 1

V =( 2gh ) ½

V = (2×10×5)½

V=10m/s

So ,
Momentum = mass × velocity
= 500 /1000 ×10= 5 kg m/s

Answer 2

➡️given :-

mass =500g

hight =5m

acceleration due to gravity =10 m/s²

>>u=0m/s

>> by applying motion formula... we get

>>> v^2-u^2 =2as
>>>v^2 = (2×5×10)+(0×0)
>>v^2 = 100
>>>v =10 m/s.

now we know that momentum =velocity ×mass
= 0.5×10
=5 kg m/s

Hence, 5kg m/s is the momentum of the body.