an object of mass 5kg falls from rest through a vertical distance of 20m and attains a velocity of 10m/s . then the work done by the resistance of the air on the object is (g=10m/s)
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From work energy theorem work done by weight + work done by air =ΔKE
Wair=ΔKE−W(weight)
=12mv2−mgh
=12×5×(10)2−5×10×20
=−750J
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Answer:
work done by the resistance of air on object is -750J.
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