Question

an object of mass 5kg falls from rest through a vertical distance of 20m and attains a velocity of 10m/s . then the work done by the resistance of the air on the object is (g=10m/s)

Answer 1

From work energy theorem work done by weight + work done by air =ΔKE

Wair=ΔKE−W(weight)

=12mv2−mgh

=12×5×(10)2−5×10×20

=−750J

Answer 2

Answer:

work done by the resistance of air on object is -750J.