Physics, asked by surakasuladr, 10 months ago

an object of mass 5kg falls from rest through a vertical distance of 20m and acquires a velocity of 10m/s thé work done by the push of air on the object is

Answers

Answered by adi487510

5

From work energy theorem work done by weight + work done by air =ΔKE

Wair=ΔKE−W(weight)

=12mv2−mgh

=12×5×(10)2−5×10×20

=−750J

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