An object of mass 5kg is dropped from a height of 20m. Calculate the initial momentum and the momentum before striking the ground.
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okk .. actually momentum is mv so. . initial to ..zero . but. and .. before striking ..it will . s = 1/2 gt² ..
so. . 40/10=t² ..
so ..t=2 ..
now before striking. it will ..V=gt. .so v= 20 .now. . momentum is 100
so. . 40/10=t² ..
so ..t=2 ..
now before striking. it will ..V=gt. .so v= 20 .now. . momentum is 100
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Given,
U(initial velocity = 0) as object is dropped.
By applying Potential energy formula
➡U = m × g × h
➡U = 5 × 10 × 20
➡U = 1000 Joule
Using 3rd equation of motion,
▶V² - U² = 2 × A × S
▶V = 0 + 2×10×20
▶V = 400 m/sec
✨Initial momentum = Mass * U(initial velocity)
= 50 × 0
= 0
✨Momentum before striking the ground = mass × Velocity(final velocity)
= 5 × 400
= 2000 kgmsec^-1
U(initial velocity = 0) as object is dropped.
By applying Potential energy formula
➡U = m × g × h
➡U = 5 × 10 × 20
➡U = 1000 Joule
Using 3rd equation of motion,
▶V² - U² = 2 × A × S
▶V = 0 + 2×10×20
▶V = 400 m/sec
✨Initial momentum = Mass * U(initial velocity)
= 50 × 0
= 0
✨Momentum before striking the ground = mass × Velocity(final velocity)
= 5 × 400
= 2000 kgmsec^-1
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