An object of mass 70 kg is raised to a height of 10 metre above the ground what is its p if the object is allowed to fall find its ke even it is halfway down
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Given Parameters :
- Mass of the object = 70 kg
- Height of the object = 10 m
- Acceleration due to gravity = 9.8 m/s²
Unknown:
- Kinetic Energy = ?
Formulas :
- Potential Energy = mgh
- Third equation of motion = v² = u² + 2as
- Kinetic energy = ½ mv²
Answer:
Potential Energy at height 10 m :
→ Potential Energy = mgh
→ Potential Energy = 70 × 9.8 × 10
→ Potential Energy = 6860 J
Objects falls on halfway :
Here,
- Initial Velocity (u) = 0 m/s
- Distance (s) = 5 m (The object is halfway down)
- Acceleration due to gravity = 9.8 m/s²
- Final Velocity (v) = ?
Lets find (v) by Using third equation of motion :
➝ v² = u² + 2as
➝ v² = (0)² + 2(9.8)(5)
➝ v² = 98
➝ v = 9.89 m/s
Now, We can calculate Kinetic Energy
᠉ Kinetic Energy = ½ mv²
᠉ Kinetic Energy = ½ (70)(9.89)²
᠉ Kinetic Energy = ½ (70)(97.8121)
᠉ Kinetic Energy = ½ (6486.847)
᠉ Kinetic Energy = 3423.4235 J
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