Question

an object of mass 70kg is raised to a height of 10 meters above the ground. what it's it potential energy. if the object is allow to fall find its kinetic energy when it is half way down

Answer 1

Answer:

the answer is explained above

Answer 2

The kinetic energy of the object when it is allowed to fall when it is half way down is 3423.42 J.

Explanation:

It is given that,

Mass of the object, m = 70 kg

Height above which it is taken, h = 10 m

The potential energy of the particle is said to be possessed by virtue of its position. It is given by :

$P=mgh$

$P=70\times 9.8\times 70$

P = 48020 J

When the object is half way down i.e. d = 5 m

let v is the velocity of the object. It can be calculated using third equation of motion as :

$v^2-u^2=2ad$

$v^2=2ad$

$v^2=2\times 9.8\times 5$

v = 9.89  m/s

So, when the object is allow to fall, let K is its kinetic energy. It is given by :

$K=\dfrac{1}{2}mv^2$

$K=\dfrac{1}{2}\times 70\times (9.89)^2$

K = 3423.42 J

So, the kinetic energy of the object when it is allowed to fall when it is half way down is 3423.42 J. Hence, this is the required solution.

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