an object of mass 80 kg moving with velocity 2m/s hit by collid with another object of mass 20 kg moving with velocity 4m/s find the loss of energy assuning the inelastic collision
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Answer:
The loss in the kinetic energy is 32 J.
Explanation:
Given;-
Mass of 1st body , m₁ = 80 kg
Mass of 2nd body, m₂ = 20 kg
Velocity of 1st body , u₁ = 2 m/s
Velocity of 2nd body, u₂ = 4 m/s
So, relative velocity, u = 4 - 2 = 2 m/s
Now, we know that for an inelastic collision the loss in the kinetic energy is given by ;-
Δ K.E. = 1/2 × (m₁m₂) × u²/ ( m₁ + m₂)
Putting the given values in the formula, we get;-
Δ K.E. = 1/2 × 20 × 80 × 2²/ 100
Δ K.E. = 800/ 100 × 4
Δ K.E. = 8 × 4
Δ K.E. = 32 J
Hope it helps! ;-))
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