Question

an object of mass m is allowed to fall freely from point a as shown in figure calculate the total mechanical energy at point a to point b point state the law which is verified by your calculation in part 123​

Answer 1

Answer:

Point A :

Kinetic energy is zero i.e. K=0

Potential energy U=mg(x+y)

Total energy T=U+K=mg(x+y)

Point B :

Velocity v=

2g(x)

Kinetic energy K=

2

1

mv

2

=mg(x)

Potential energy U=mg(y)

Total energy T=U+K=mg(x+y)

Point C :

Velocity v=

2g(x+y)

Kinetic energy K=

2

1

mv

2

=mg(x+h)

Potential energy U=0

Total energy T=U+K=mg(x+y)

The above parts verifies the law of conservation of energy.

Explanation: