Question

An object of mass m is moving with a velocity v on a level ground state the work done by a person who wants to stop the object

Answer 1

Answer:

1/2 m× v^2

Explanation:

USE THE FORMULA

WORK DONE = CHANGE IN KINETIC ENERGY

SO, W = 1/2 m ( vf^2 - vi^2)

WHERE vf IS THE FINAL VELOCITY AND vi IS THE INITIAL VELOCITY

NOW HERE vf = 0 and vi= v

SO, WORK DONE BY THE PERSON = - (- 1/2 m v^2)

W = 1/2 mv^2