an object of mass M is sliding with a velocity of 4 m s on a frictionless horizontal surface the retarding force necessary to stop the object is 1second is
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Answer:
(-4M) N
Explanation:
Given:
u=4m/s
v=0m/s , because to stop means velocity must be 0.
t= 1 sec
Now, a= (v-u) /t= -4m/s^2
Therefore force required=F
F=ma = M×(-4) = (-4M) N
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