an object of mass 'm' when raised to a height 'h' possesses P.E of 100J.find the new P.E if the same object is rised to heigh h/2.(P.E= potential energy)
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100J=mx10xh
mxh=10
m=10/h
P.E'=mx10xh/2
P.E'=5mh
m=P.E'/5h
10/h=P.E'/5h
10=P.E'/5
P.E'=50J
New P.E becomes half of previous one.
mxh=10
m=10/h
P.E'=mx10xh/2
P.E'=5mh
m=P.E'/5h
10/h=P.E'/5h
10=P.E'/5
P.E'=50J
New P.E becomes half of previous one.
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