An object of sixe 7.0 cm is placed at 27 cm in front of a concave mirror of focal length 18
cm. At what distance from the mirror should a screen be placed , so that a sharp focused
images can be obtained? Find the size and the nature of the image .
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u = - 27 cm, f = - 18 cm. ho= 7.0 cm
1/v = 1/f- 1/u
1/v = -1/18 + 1/27 = -1/54
V = - 54 cm.
Screen must be placed at a distance of 54 cm from the mirror in front of it.
hi/h0= v/u
hi/h0= v/u
hi/7 = +54/-27
hi = -2 x 7 = -14 cm.
Thus, the image is of 14 cm length and is inverted image.
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