An object of size 0.7 cm is placed at 27 cm in front of a concave mirror of focal length 18 cm. At what distance from the mirror should a screen be placed , so that a sharp focussed image can be obtained ? Find the size and nature of the image .
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We get the image size to be double the object size with a negative sign. This means that the image formed will be real and inverted in nature. The image formed by the object in front of a concave mirror is 14 cm in size, is 54 cm in front of the mirror and is real and inverted in nature. This is the required solution
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Since sharp image will appear where all the reflected rays meet I.e the image distance ( v)
Given
Object distance ( u) - - 27
F= -18 hence by mirror formula screen should be placed 54 cm away from mirror
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