An object of size 1 cm is placed at a distance of 15 cm in front of a convex lens of focal length 10 cm. Find the nature, size and the location of the image
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HEY MATE...
height of object=1 cm
object distance= -15 cm
focal length= 10 cm
image distance=?
height of image=?
LET'S FIND.....
1/f = 1/v-1/u
1/10=1/v-1/-15
1/v=1/10-1/15
1/v=1/30
v=30 cm
hence,image distance=30 cm
NOW,
m=-v/u= -height of image /h of object
i.e -30/-15=-v/1
30/15=-v/1
-v=2
i.e v= -2
hence, height of image = -2 cm
Since,the image formed is negative hence the image is real and inverted.
and the image is located at the right side of the lens.
HOPE IT HELPED.
PLZ......MARK AS BRAINLIEST..✌️✌️✌️
height of object=1 cm
object distance= -15 cm
focal length= 10 cm
image distance=?
height of image=?
LET'S FIND.....
1/f = 1/v-1/u
1/10=1/v-1/-15
1/v=1/10-1/15
1/v=1/30
v=30 cm
hence,image distance=30 cm
NOW,
m=-v/u= -height of image /h of object
i.e -30/-15=-v/1
30/15=-v/1
-v=2
i.e v= -2
hence, height of image = -2 cm
Since,the image formed is negative hence the image is real and inverted.
and the image is located at the right side of the lens.
HOPE IT HELPED.
PLZ......MARK AS BRAINLIEST..✌️✌️✌️
khushi65041:
plz...mark as BRAINLIEST
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