An object of size 5.0cm is placed 30cm in front of concave mirror of focal length 15m at what distance should be a screen be placed so that a sleep focused image can be obtained find the size and the nature of the image
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We would have to place the screen at 30 cm in front of the mirror so as to obtain a sharp image of the object .The size of the object would be same as the object(i.e.5.0 cm) and the image formed is real and inverted.
Explanation:
We see that the object is placed at the centre of curvature (C=2f=2×15=30 cm)and object placed at C gives us a real and inverted image of the same size.
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