- An object of size 7.0 cm is placed at 27 cm in front of a concave mirror of focal length
18 cm. At what distance from the mirror should a screen be placed so that a sharp focussed image can be
obtained ? Find the size and nature of image.
Answers
Answered by
8
Answer:
Mirror formula :
v1+u1=f1...........(1)
So, u=−27cm
Concave mirror have negative focal length.
f=−18cm
Putting the values in (1),
v1+−271=−181
We get , v=−54cm
Also,
Magnification = h1h2=u−v
7.0h2=−−27−54
h2=−14.0cm
Image will be real and inverted and will be of size 14 cm.
Answered by
9
•GIVEN:-
SOLUTION :-
•The screen should be placed at a distance of 54cm in front of the given mirror
•Negative value of magnification shows that image is real.
➽The height of the image is negative which shows that image is inverted.
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